I did a chem lab and have to figure out some stuff off of some data I found during the lab
Weight of empty crucible and cover: 19.74 g
Weight of crucible, cover and hydrated salt: 22.74 g
Weight of crucible, cover and hydrated salt after 1st heating: 22.13 g
Weight of crucible, cover and hydrated salt after 2nd heating: 22.56 g
Weight of crucible, cover and hydrated salt after 3rd heating: 21.54 g
Calculate the weight of the hydrated salt.
Calculate the weight of the anhydrous salt.
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To calculate the weight of the hydrated salt, you need to subtract the weight of the empty crucible and cover from the weight of the crucible, cover, and hydrated salt.
Weight of hydrated salt = weight of crucible, cover, and hydrated salt - weight of empty crucible and cover
Weight of hydrated salt = 22.74 g - 19.74 g
Weight of hydrated salt = 3 g
To calculate the weight of the anhydrous salt, you need to subtract the weight of the crucible, cover, and hydrated salt after the 3rd heating from the weight of the empty crucible and cover.
Weight of anhydrous salt = weight of empty crucible and cover - weight of crucible, cover, and hydrated salt after 3rd heating
Weight of anhydrous salt = 19.74 g - 21.54 g
Weight of anhydrous salt = -1.8 g
It seems like there might be an error in the measurements because the weight of the anhydrous salt is negative. Please double-check your data and calculations.
Calculate the weight of the water lost by heating.
Calculate the percentage of water in the hydrate.
Calculate the number of moles of H2O lost by heating.
Calculate the number of moles of anhydrous salt.
Enter the formula of the hydrated salt.
Calculate the theoretical percentage of the water in the hydrate.
Calculate the experimental error.
Calculate the percentage error.