The imaginary compound calcium nortonate, CaNtO4, is 54.698% nortonium, Nt, by weight. Calculate the percent, by weight, of potassium in potassium nortonate to four significant digits.

If we write calcium nortonate as CaNtO4 then potassium nortonate would be K2NtO4.

Fraction Nt in CaNtO4 = [Nt/(Ca+Nt+4*O)] = 0.54698. Substituting atomic masses we have [x/(40.08+x+64)] = 0.54698. Note that since the answer is to be to 4 s.f. you should confirm these atomic masses and use the more accurate one. The idea is to determine the atomic mass of x = Nt.
Now you can determine the molar mass of K2NtO4. %K = (2*atomic mass K/molar mass K2NtO4)]*100 = ?

thank you so much!!

To calculate the percent by weight of potassium in potassium nortonate, we need to determine the molar mass of potassium nortonate (KNO3) and the molar mass of potassium (K).

The molar mass of calcium nortonate (CaNtO4) is given by:
Ca: 1 atom x 40.08 g/mol = 40.08 g/mol
Nt: 1 atom x molar mass Nt = molar mass Nt
O: 4 atoms x 16.00 g/mol = 64.00 g/mol

To find the molar mass of nortonium (Nt), we can use the given information that calcium nortonate is 54.698% nortonium by weight. Since the remaining percentage must be oxygen, we can assume the molar mass of nortonium is equal to the molar mass of calcium nortonate minus the molar mass of oxygen.

So, the molar mass of nortonium is given by:
molar mass Nt = (molar mass CaNtO4) - (molar mass O)
Let's denote molar mass Nt as x.

x = (40.08 g/mol + x + 64.00 g/mol) - (16.00 g/mol x 4)
x = 40.08 g/mol + x + 64.00 g/mol - 64.00 g/mol
-3x = 40.08 g/mol
x = -13.36 g/mol

Since the molar mass cannot be negative, there has been an error in the given information. The molar mass of nortonium cannot be determined with the given data.

Therefore, it is not possible to calculate the percent by weight of potassium in potassium nortonate without the molar mass of nortonium.

To determine the percent, by weight, of potassium in potassium nortonate (KNO₄), we need to make use of the information provided about calcium nortonate (CaNtO₄).

Given that calcium nortonate (CaNtO₄) is 54.698% nortonium (Nt) by weight, we can infer that the remaining percentage accounts for the other elements in the compound, which in this case is potassium (K) and oxygen (O).

To calculate the percent, by weight, of potassium in potassium nortonate (KNO₄), we first need to determine the molar mass of the compound.

The molar mass of KNO₄ can be calculated by summing the atomic masses of all the constituent elements:
- The atomic mass of potassium (K) is approximately 39.10 g/mol.
- The atomic mass of nitrogen (N) is approximately 14.01 g/mol.
- The atomic mass of oxygen (O) is approximately 16.00 g/mol (since there are four oxygen atoms in KNO₄).

Now we can calculate the molar mass:
Molar mass of KNO₄ = (1 × atomic mass of K) + (1 × atomic mass of N) + (4 × atomic mass of O)
= (1 × 39.10 g/mol) + (1 × 14.01 g/mol) + (4 × 16.00 g/mol)
= 39.10 g/mol + 14.01 g/mol + 64.00 g/mol
= 117.11 g/mol

Next, we need to determine the molar mass of nortonium (Nt). However, the atomic mass of nortonium is not provided in the question. Therefore, it is not possible to directly calculate the percent, by weight, of potassium in potassium nortonate without the necessary information.

If you have additional information or the atomic mass of nortonium (Nt), please provide it so that I can help you further.