The Marshmellow man tromps along the streets of New York City with his blue sailor hat on. He tries to climb up a building to reach Ghostbusters and a gargoyle statue falls 326m to the street below. What height is the gargoyle when it reaches a velocity of 59 m/s?
v = at = 9.8t
59 = 9.8t
t = 6.0s
during those 6 seconds,
h = 326 - 4.9t^2 = 149.6m
To determine the height of the gargoyle when it reaches a velocity of 59 m/s, we need to make use of kinematic equations. Specifically, we can use the equation:
v^2 = u^2 + 2as
Where:
v is the final velocity (59 m/s),
u is the initial velocity (0 m/s, assuming the gargoyle was initially at rest),
a is the acceleration (in this case, due to gravity: 9.8 m/s^2),
and s is the displacement (the distance the gargoyle falls, in this case).
We can rearrange the equation to solve for s:
s = (v^2 - u^2) / (2a)
Plugging in the values:
s = (59^2 - 0^2) / (2 * 9.8)
s = (3481 - 0) / 19.6
s = 177.56 m
Therefore, when the gargoyle reaches a velocity of 59 m/s, it will have fallen approximately 177.56 meters.