A brick dropped from a roof hits the ground 3.29 seconds later. How high (in m) was the roof?
You can replace the value of time from 3.64 to 3.29
S=vit+1/2at^2
H=0+0.5 (9.8)(3.64)^2
H=64.9=65
To calculate the height of the roof, we can use the equation of motion for free fall:
h = (1/2) * g * t^2
Where:
h = height of the roof
g = acceleration due to gravity (approximately 9.8 m/s^2)
t = time taken for the brick to hit the ground (3.29 seconds)
Substituting the given values into the equation:
h = (1/2) * 9.8 * (3.29)^2
h = 0.5 * 9.8 * 10.8241
h ≈ 53.3059 m
Therefore, the height of the roof is approximately 53.31 meters.
To determine the height of the roof, we can use the laws of physics and the equations of motion. Specifically, we can use the equation for free fall:
h = (1/2) * g * t^2
Where:
h is the height of the roof,
g is the acceleration due to gravity (approximately 9.8 m/s^2),
t is the time it takes for the brick to fall.
Given that the brick takes 3.29 seconds to hit the ground, we can substitute this value into the equation and solve for h:
h = (1/2) * 9.8 m/s^2 * (3.29 s)^2
Simplifying the equation:
h = (1/2) * 9.8 m/s^2 * 10.8241 s^2
h ≈ 53.59 m
Therefore, the roof is approximately 53.59 meters high.