A typical brick has dimensions of 20.0 cm by 10.0 cm by 5.0 cm and weighs 20.0 N. How does the pressure exerted by a typical brick when it is resting on its smallest side compare to the pressure exerted when it is resting on its largest side
PLEASE HELP !!
thanks!
surface area doesnt effect pressure exerted
You know the weight of the brick.
Then divide weight by area small end.
Divide weight by largest side.
To calculate the pressure exerted by the brick, we need to divide the weight of the brick by the area of the surface it is resting on. The pressure exerted by an object is determined by the force it exerts over a given area.
First, let's calculate the surface area of the smallest side of the brick. The smallest side has dimensions of 20.0 cm by 5.0 cm, so the area can be found by multiplying the length and the width:
Area of smallest side = length × width = 20.0 cm × 5.0 cm = 100.0 cm²
Next, divide the weight of the brick by the area of the smallest side to find the pressure exerted:
Pressure on smallest side = weight / area of smallest side = 20.0 N / 100.0 cm² = 0.2 N/cm²
Now, let's calculate the surface area of the largest side of the brick. The largest side has dimensions of 20.0 cm by 10.0 cm, so the area can be found in the same way:
Area of largest side = length × width = 20.0 cm × 10.0 cm = 200.0 cm²
Again, divide the weight of the brick by the area of the largest side to find the pressure exerted:
Pressure on largest side = weight / area of largest side = 20.0 N / 200.0 cm² = 0.1 N/cm²
Comparing the two pressures, we can see that the pressure exerted when the brick is resting on its smallest side (0.2 N/cm²) is twice as much as the pressure exerted when it is resting on its largest side (0.1 N/cm²).