A jet makes a landing traveling due east with a speed of 100 m/s. If the jet comes to rest in 15.0 s, what is the magnitude and direction of its average acceleration?
due west or due east?
How can I solve this question? You don't have to give me the answer but how you derive to that would be perfect. thanks
v=v₀-at
v=0
v₀= at
a= v₀/t=100/15=6.67 m/s² (due East)
6.67
To solve this question, we need to use the equation for average acceleration:
acceleration = (final velocity - initial velocity) / time
Given that the jet comes to rest, its final velocity is 0 m/s. The initial velocity is 100 m/s (since it is traveling due east), and the time is 15.0 s.
Substituting these values into the equation, we have:
acceleration = (0 m/s - 100 m/s) / 15.0 s
This simplifies to:
acceleration = -100 m/s / 15.0 s
Thus, the magnitude of the average acceleration is approximately 6.67 m/s².
Since the initial velocity is in the east direction and the acceleration is negative, the direction of the average acceleration is due west.
To solve this question, you can use the equations of motion to find the average acceleration of the jet.
First, recall that acceleration is defined as the rate of change of velocity. In other words, it is the change in velocity divided by the change in time.
The initial velocity of the jet is 100 m/s to the east, and the final velocity is 0 m/s since it comes to rest. The change in velocity can be calculated as the difference between the final and initial velocities: Δv = vf - vi.
Here, the initial velocity vi is 100 m/s to the east, and the final velocity vf is 0 m/s. So, the change in velocity Δv is 0 - 100 = -100 m/s.
The change in time Δt is given as 15.0 s.
Now, you can use the formula for acceleration to find the average acceleration of the jet:
average acceleration = Δv / Δt
Substituting the values, we have:
average acceleration = (-100 m/s) / (15.0 s)
Calculating this, you find that the average acceleration is approximately -6.67 m/s².
The negative sign indicates that the average acceleration is in the opposite direction of the initial velocity. Since the initial velocity is to the east, the average acceleration is in the opposite direction, i.e., due west.
Therefore, the magnitude of the average acceleration is 6.67 m/s² and its direction is due west.