A jet makes a landing traveling due east with a speed of 110 m/s. If the jet comes to rest in 11.0 s, what is the magnitude and direction of its average acceleration?
you don't have to give me the answer but a step by step on how to solve this would help very much. thanks
v = a * t, where v is speed, a is acceleration, and t is time
110 m/s = a * 11
Solve for a
Jennifer
Thank you!
To find the magnitude and direction of the average acceleration, we can use the equation:
Average acceleration = (Final velocity - Initial velocity) / Time
1. First, determine the initial velocity: Since the jet is traveling due east, its initial velocity is 110 m/s to the east.
2. Next, determine the final velocity: The jet comes to rest, which means its final velocity is 0 m/s.
3. Calculate the change in velocity: Final velocity - Initial velocity = 0 m/s - 110 m/s = -110 m/s (note the negative sign indicating that the change is in the opposite direction).
4. Determine the time: The time given in the question is t = 11.0 s.
5. Calculate the average acceleration: Average acceleration = (-110 m/s) / (11.0 s) = -10 m/s^2
So the magnitude of the average acceleration is 10 m/s^2, and since it is in the opposite direction of the initial velocity, the direction of the average acceleration is west.
To find the magnitude and direction of the average acceleration, you can use the formula:
Average acceleration (a) = (final velocity - initial velocity) / time
Step 1: Identify the given values in the problem:
- Initial velocity (u) = 110 m/s (eastward)
- Final velocity (v) = 0 m/s (since the jet comes to rest)
- Time (t) = 11.0 s
Step 2: Substitute the given values into the formula:
a = (0 m/s - 110 m/s) / 11.0 s
Step 3: Perform the subtraction:
a = (-110 m/s) / 11.0 s
Step 4: Calculate the magnitude of the average acceleration:
|a| = |-110 m/s / 11.0 s| = 10 m/s^2
Step 5: Determine the direction of the average acceleration.
Since the jet is traveling eastward and comes to rest, the average acceleration is in the opposite direction. Therefore, the direction of the average acceleration is westward.
So, the magnitude of the average acceleration is 10 m/s^2, and the direction is westward.