The radius of a merry-go-round is 7 meters, and it takes 12 seconds to make a complete revolution. What is the speed of an atom on the outer rim?
v=2πR/t=2•π•7/12=3.67 m/s.
To calculate the speed of an atom on the outer rim of a merry-go-round, we first need to find the circumference of the merry-go-round (which corresponds to the path traveled by the atom during a complete revolution). The circumference can be calculated using the formula:
Circumference = 2 * π * radius
Substituting the given radius value of 7 meters, we have:
Circumference = 2 * π * 7
Circumference ≈ 2 * 3.14 * 7 ≈ 43.96 meters
Now, we know that the atom takes 12 seconds to travel the entire circumference. To find the speed of the atom, we divide the circumference by the time it takes to complete one revolution:
Speed = Circumference / Time
Speed = 43.96 meters / 12 seconds ≈ 3.66333 meters per second (rounded to 5 decimal places)
Therefore, the speed of an atom on the outer rim of the merry-go-round is approximately 3.66333 meters per second.