A jet makes a landing traveling due east with a speed of 100 m/s. If the jet comes to rest in 15.0 s, what is the magnitude and direction of its average acceleration?
m/s2
due west
due east
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To find the magnitude and direction of the average acceleration, we can use the equation:
Average acceleration = (final velocity - initial velocity) / time
First, let's determine the final velocity. Since the jet comes to rest, the final velocity will be zero.
Final velocity (v_f) = 0 m/s
Given that the initial velocity (v_i) is 100 m/s and the time (t) is 15.0 s, we can now substitute these values into the equation to find the average acceleration.
Average acceleration = (0 m/s - 100 m/s) / 15.0 s
To simplify the equation, we subtract the initial velocity from zero:
Average acceleration = (-100 m/s) / 15.0 s
Now we can calculate the average acceleration:
Average acceleration = -6.67 m/s^2
The negative sign indicates that the acceleration is in the opposite direction of the initial velocity, which is due west. Therefore, the magnitude of the average acceleration is 6.67 m/s^2, and the direction is due west.