Nitric acid reacts with silver metal: 4HNO3 + 3Ag -> NO + 2H2O + 3AgNO3. Calculate the number of grams of NO formed when 10.8 g of Ag reacts with
12.6 g HNO3
30.3
To calculate the number of grams of NO formed when 10.8 g of Ag reacts with 12.6 g of HNO3, we need to use stoichiometry. Stoichiometry is a mathematical relationship between the amount of reactants and the products of a chemical reaction.
1. Determine the moles of the given substances:
- Moles of Ag = Mass of Ag / Molar mass of Ag
- Moles of HNO3 = Mass of HNO3 / Molar mass of HNO3
The molar mass of Ag is 107.87 g/mol, and the molar mass of HNO3 is 63.01 g/mol.
2. Find the limiting reactant:
To determine the limiting reactant, compare the moles of each reactant to the stoichiometric ratios given in the balanced equation. The reactant that produces the least amount of product is the limiting reactant.
3. Calculate the moles of NO formed using the stoichiometry:
- From the balanced equation, we can see that 3 moles of Ag react with 4 moles of HNO3 to produce 1 mole of NO.
- Use the stoichiometric coefficients to convert the moles of the limiting reactant (Ag or HNO3) to the moles of NO.
4. Convert moles of NO to grams:
- Use the molar mass of NO (30.01 g/mol) to convert moles of NO to grams.
Follow these steps to find the answer to the question.
on the reactants, 4 moles nitric to 3 moles silver.
calculate the masses in grams to moles for Ag, HNO3. Do you have a 4:3 ratio? If less, then you have excess Ag. If more, then you have Ag as the limiting reagant.
so if the ratio is more, then look the ratio of Ag to NO in the equation. For each mole of Ag, you get one mole of NO.
If it is less, then all the Ag doesn't react. For each 4 moles HNO3 (calculate how many you have) you get 3/4 of that in moles NO