Stephanie serves a volleyball from a height
of 0.85 m and gives it an initial velocity of
+6.6 m/s straight up.
How high will the volleyball go? The accel-
eration of gravity is 9.81 m/s2.
Answer in units of m
To determine the maximum height reached by the volleyball, we can use the kinematic equation for vertical motion.
The equation is:
vf^2 = vi^2 + 2ad
Where:
vf = final velocity (0 m/s at the highest point)
vi = initial velocity (+6.6 m/s)
a = acceleration due to gravity (-9.81 m/s^2, since it acts against the upward motion)
d = displacement (unknown)
Rearranging the equation to solve for displacement (d), we have:
d = (vf^2 - vi^2) / (2a)
Plugging in the given values:
d = (0^2 - 6.6^2) / (2 * -9.81)
Calculating this equation gives us the displacement (d) which represents the height reached by the volleyball. Let's solve it:
d = (-43.56) / (-19.62)
d ≈ 2.22 m
Therefore, the volleyball will go approximately 2.22 meters high.
hmax = ho + (V^2-Vo^2)/2g.
hmax = 0.85 + (0-43.56)/-19.62 = 3.07 m.
= Ht. above gnd.