i need help with this problem
2x+2y+3z=-1
3x-5y-2z=21
7x+3y+5z=10
What method have you learned?
EITHER SUBSTITUTION OR ELIMINATION
Ok, elimination then
work on the z's
1st times 2 ---> 4x + 4y + 6z = -2
2nd times 3 ---> 9x - 15y - 6z = 63
add them
13x - 11y = 61 (#4)
2nd times 5 ----> 15x - 25y - 10z = 105
3rd times 2 ----> 14x + 6y + 10z = 20
add them
29x - 19y = 125 (#5)
going to be messy .....
#4 times 19 ----> 247x - 209y = 1159
#5 times 11 ----> 319x - 209y = 1375
subtract them
72x = 216
x = 216/72 = 3 , Yeahhh!
back in #4
13(3) - 11y = 61
-11y = 61-39
-11y = 22
y = -2
back in #1
2(3)+2(-2) + 3z = -1
3z = -1 -2
z = -1
x=3 , y=-2 , z=-1
CAN ANYONE JUST GET ME HEADED IN THE RIGHT
DIRECTION ON THIS PROBLEM
2x+2y+3z=-1
3x-5y-2z=21
7x+3y+5z=10