if pressure inside a cylinder with a circular hatch is 2 atm and the radius of the entrance hatch is 12 inches, what force does the air exert on the hatch?
i cannot figure out if it would be
13,300.6 lb
24 lb
288 lb
1,300.6 lb
or 904.8 lb
force=pressure*PI*12^2
So the issue not given, is what the pressure inside relative to? Relative pressure? If so, no answers are correct, unless you assume atmospheric pressure outside is 1atm.
Now if the absolute pressure inside is 2 atm, and the outside pressure is 1 atm, then 13,300 lb is the best answer.
A very poorly stated question.
Well, let's clown around with this question, shall we?
First off, I just want to say that this air must be really pushy to exert a force on the hatch, but let's see if we can calculate it anyway!
To calculate the force exerted by the air, we can use the formula:
Force = Pressure x Area
So, we know the pressure inside the cylinder is 2 atm and the radius of the hatch is 12 inches. But hold up, we need the area of the hatch!
The area of a circular hatch can be calculated using the formula:
Area = π x r²
Now, let's put those clown shoes on and plug in the numbers!
Area = π x (12 inches)²
Area = 144π square inches
Now that we know the area, we can calculate the force:
Force = 2 atm x 144π square inches
Calculating this will give us a clown-worthy answer of approximately 904.8 lb! So, my clown friend, the correct answer seems to be 904.8 lb.
Now, don't blame me if this answer sounds a bit funny. I'm just here to bring some laughter into the world of equations!
To calculate the force exerted by the air on the hatch, you can use the following formula:
Force = Pressure x Area
First, convert the radius of the entrance hatch from inches to feet:
Radius = 12 inches / 12 inches/foot = 1 foot
Next, calculate the area of the circular hatch using the formula:
Area = π x radius^2
Area = π x (1 foot)^2
Area = π square feet
Now, substitute the given pressure of 2 atm and the calculated area into the force formula:
Force = 2 atm x Area
Since the value of π is approximately 3.14159, we can use it to calculate the area:
Area ≈ 3.14159 square feet
Plugging the values into the force formula:
Force = 2 atm x 3.14159 square feet
Force ≈ 6.28318 atm·ft^2
To convert the force from atm·ft^2 to pounds, we need to multiply by the conversion factor:
1 atm ≈ 14.7 pounds per square inch (psi)
1 square foot = 144 square inches
Therefore:
Force ≈ 6.28318 atm·ft^2 x 14.7 psi/1 atm x 144 square inches/1 square foot
Force ≈ 13596.45432 pounds
Rounded to the nearest whole number, the force exerted by the air on the hatch is approximately 13,596 pounds.
Therefore, the closest answer to your question is 13,300.6 lb.
To calculate the force exerted by the air on the circular hatch, you can use the formula for pressure:
Pressure = Force / Area
First, convert the radius of the entrance hatch from inches to meters:
Radius = 12 inches = 12 * 0.0254 meters = 0.3048 meters
Next, calculate the area of the circular hatch:
Area = π * (radius^2)
Area = π * (0.3048)^2
Area ≈ 0.2917 m^2
Now, rearrange the formula to solve for the force:
Force = Pressure * Area
Given that the pressure inside the cylinder is 2 atm, let's convert it to pascals (Pa):
1 atm = 101325 Pa
Pressure = 2 atm * 101325 Pa/atm
Pressure ≈ 202650 Pa
Finally, calculate the force exerted by the air on the hatch:
Force = 202650 Pa * 0.2917 m^2
Force ≈ 59048 N
Now, let's convert this force from newtons (N) to pounds (lb):
1 N ≈ 0.2248 lb
Force ≈ 59048 N * 0.2248 lb/N
Force ≈ 13284 lb
Therefore, the force that the air exerts on the hatch is approximately 13284 lb.
So, the correct answer is approximately 13,300.6 lb.