254 g of copper sulphate, CuSO4 is dissolved in water to produce 650 ml of solution. Determines the degree of concentration of the solution in mol / L.
mols CuSO4 = grams/molar mass
M CuSO4 = mols/L soln.
To determine the concentration of the solution in mol/L, we need to calculate the number of moles of copper sulphate (CuSO4) present in the solution first.
Step 1: Calculate the molar mass of CuSO4
The molar mass of copper (Cu) is 63.55 g/mol.
The molar mass of sulfur (S) is 32.06 g/mol.
The molar mass of oxygen (O) is 16.00 g/mol (there are four oxygen atoms in CuSO4).
Adding them up gives us:
Molar mass of CuSO4 = (63.55 g/mol) + (32.06 g/mol) + (16.00 g/mol x 4) = 159.61 g/mol
Step 2: Calculate the number of moles of CuSO4 in the solution
Number of moles = mass / molar mass
Number of moles = 254 g / 159.61 g/mol = 1.59 mol
Step 3: Calculate the volume of the solution in liters
The volume is given as 650 mL. We need to convert it to liters by dividing by 1000.
Volume = 650 mL / 1000 = 0.65 L
Step 4: Calculate the concentration of the solution in mol/L
Concentration = number of moles / volume
Concentration = 1.59 mol / 0.65 L = 2.45 mol/L
Therefore, the concentration of the solution is 2.45 mol/L.