the perimeter of an athletic field is 104 meters and the length is 12 meters more than the width find the width and the length.
width --- x m
length ---- x+12 m
2x + 2(x+12) = 104
easy from here, just solve for x, and back-substitute.
(oddly shaped athletic field , basketball-court is 28 m by 15 m, volleyball is 18 by 9, tennis 24 m by 11m etc
To find the width and length of the athletic field, we can set up an equation based on the given information.
Let's assume the width of the athletic field is "x" meters. Since the length is 12 meters more than the width, we can express the length as "x + 12" meters.
The perimeter of a rectangle is calculated by adding all four sides. In this case, the perimeter is given as 104 meters.
So, the equation for the perimeter is:
2(width) + 2(length) = perimeter
2(x) + 2(x + 12) = 104
Now, let's solve the equation step-by-step:
2x + 2(x + 12) = 104
2x + 2x + 24 = 104
4x + 24 = 104
4x = 104 - 24
4x = 80
x = 80 / 4
x = 20
Therefore, the width of the athletic field is 20 meters.
And the length is:
x + 12 = 20 + 12 = 32
So, the length of the athletic field is 32 meters.
To find the width and length of the athletic field, we can set up a system of equations based on the given information:
Let's assume that the width of the field is represented by "W" meters.
Since the length of the field is 12 meters more than the width, we can represent the length as "W + 12" meters.
The perimeter of a rectangle is calculated by adding the lengths of all four sides. In this case, the perimeter is given as 104 meters.
The formula for the perimeter of a rectangle is: Perimeter = 2(Length + Width)
Plugging in the given information:
104 = 2(W + W + 12)
Simplifying the equation:
104 = 2(2W + 12)
52 = 2W + 12
40 = 2W
W = 20
So the width of the athletic field is 20 meters.
To find the length, we substitute the value of the width back into one of the equations:
Length = W + 12 = 20 + 12 = 32 meters
Therefore, the length of the athletic field is 32 meters and the width is 20 meters.