The metabolic oxidation of glucose, C6H12O6, in our bodies produces CO2, which is expelled from our lungs as a gas.
C6H12O6(aq) + 6 O2(g) → 6 CO2(g) + 6 H2O(l)
Calculate the volume of dry CO2 produced at body temperature (37°C) and 0.980 atm when 25.5 g of glucose is consumed in this reaction.

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asked by jake
  1. mols glucose = 25.5g/molar mass glucose.
    mols CO2 produced = 6x that (Look at the coefficients in the balanced equation.)
    Use PV = nRT and solve for volume at the conditions listed. Remember T must be in kelvin.

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