2 liters of N2 at 0 degree Celsius and 5 atm pressure are expanded isothermally against a constant pressure of 1 atm until the pressure of the gas is also 1 atm. Assuming the gas to be ideal, what are the values of work,delta E, delta H, and q for the process?
P1 V1 =P2V2 ,
P1=5atm, V1= 2litre, P2=1atm find v2 by above eq.
then put it into -
-px(V2-V1) where pexternl = 1atm
so - 1(10-2)= - 8litreatm
1 litre atm =101.3 joules so multiply it
-8× 101.3 = - 810.4joule
i need the answer too
To find the values of work (W), ΔE (change in internal energy), ΔH (change in enthalpy), and q (heat transfer) for the given isothermal expansion process, we can use the ideal gas equation and the formulas for work, internal energy, enthalpy, and heat transfer.
First, let's calculate the volume of the gas at the final pressure of 1 atm. We know that the gas is expanded isothermally, which means the temperature remains constant. Therefore, we can use the ideal gas equation:
PV = nRT
Where:
P = pressure
V = volume
n = number of moles
R = ideal gas constant
T = temperature in Kelvin
We are given:
P1 = 5 atm
V1 = 2 liters
P2 = 1 atm (final pressure)
Rearranging the equation to solve for V2, we have:
V2 = (nRT2) / P2
Since the temperature is constant, T2 = T1 = 0 degrees Celsius, which needs to be converted to Kelvin:
T2 = T1 + 273 = 0 + 273 = 273 K
V2 = (nR * 273 K) / 1 atm
Now, let's calculate the values one by one:
1. Work (W):
The work done during the isothermal process can be calculated using the formula:
W = -PΔV
Given that the pressure is constant during the expansion process, W can be written as:
W = -P2(V2 - V1)
Substituting the known values:
W = -1 atm * (V2 - V1)
2. ΔE (Change in Internal Energy):
For an isothermal process, the change in internal energy (ΔE) is zero because the temperature remains constant. Therefore, ΔE = 0.
3. ΔH (Change in Enthalpy):
Since the process is isothermal, ΔH is equal to the change in internal energy. Therefore, ΔH = 0.
4. q (Heat Transfer):
The heat transfer during an isothermal process can be calculated using the following formula:
q = ΔE + W
Since ΔE = 0, the equation simplifies to:
q = W
Now, we can substitute the calculated values to determine W and q:
W = -1 atm * (V2 - V1)
q = W
To calculate the final volume, we need the number of moles of N2 (n) in the system. Unfortunately, that information is not mentioned in the question.