Calculus help!

f(x)=e^x for 0<x<2. Imagine that you have graphed this function in the x-y plane. For each value of x in the domain, erect a square above the curve perpendicular to the x-axis and parallel to the y-z plane where one side runs from the x-axis to the curve. So the square at x=.9 has vertices (.9,0,0), (.9,e^.9,0), (.9,e^.9,e^.9), (.9,0,e^.9). All of these squares together create a volume. Set up an integral to compute the volume exactly.

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  1. length of side of square = e^x
    area of square = (e^x)^2 = e^2x
    volume = integral dx e^2x from x = 0 to x = 2

    = (1/2)e^2x at x = 2 - at x = 0

    = (1/2)e^4 -(1/2)(1)
    = (1/2)(e^4 -1)

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    posted by Damon

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