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Unless otherwise stated, all objects are located near the Earth's surface, where = 9.8 .

A hockey puck with a weight of 0.80 is sliding freely across a section of very smooth (frictionless) horizontal ice.
Part A

When it is sliding freely, how does the upward force of the ice on the puck (the normal force) compare with the upward force when the puck is sitting permanently at rest?

When it is sliding freely, how does the upward force of the ice on the puck (the normal force) compare with the upward force when the puck is sitting permanently at rest?

The upward force is greater when the puck is sliding.

The upward force is less when the puck is sliding.

The upward force is the same in both situations.

The upward force is the same in both situations.

The upward force is the same in both situations

The upward force of the ice on the puck (the normal force) is the same in both situations. In both cases, whether the puck is sliding or sitting permanently at rest, the normal force is equal to the weight of the puck. This is because the normal force is the force exerted by a surface to support the weight of an object resting on it. Since the weight of the puck is determined by its mass (0.80 kg) multiplied by the acceleration due to gravity (9.8 m/s^2), the normal force will also be 0.80 kg × 9.8 m/s^2 = 7.84 N in both situations. Therefore, the answer is: The upward force is the same in both situations.