Unless otherwise stated, all objects are located near the Earth's surface, where = 9.80 .
A block of mass 23.0 slides down a frictionless surface inclined at 35.
Part A
To ensure that the block does not accelerate, what is the magnitude of the smallest force that you must exert on it?
What is its direction?
What is its direction?
down the incline
up the incline
To ensure that the block does not accelerate down the inclined surface, we need to exert a force equal in magnitude and opposite in direction to the force of gravity acting on the block.
The force of gravity acting on the block can be calculated using the formula:
Fg = m * g
Where:
Fg is the force of gravity
m is the mass of the block (given as 23.0 kg)
g is the acceleration due to gravity (given as 9.80 m/s^2)
Substituting the given values:
Fg = 23.0 kg * 9.80 m/s^2
Fg = 225.4 N
To ensure that the block does not accelerate, we need to exert a force equal to 225.4 N in the opposite direction of the force of gravity.
Since the block is sliding down the inclined surface, the force we need to exert on the block should be directed up the incline, opposite to the downward force of gravity.
Therefore, the direction of the force we need to exert is up the incline.