How would I find the volume of 30% hydrogen peroxide solution from 20mL of 3% hydrogen peroxide solution?
I think your post is stated awkwardly. I assume you want to dilute 30% H2O2 to make 20 mL of a 3% solution. If that is true, use the dilution formula.
c1v1 = c2v2.
30% x mL = 3% x 20 mL.
Solve for mL of 30% stuff you need to take
So I would multiply 3% by 20 mL which equals 0.6. Then I would divide 0.6 by 30% to get the volume of 30% hydrogen peroxide?
Yes, you want 2.0 mL of the 30% stuff. Bob Pursley likes to use parts.
To do it that way you have
From 30% to 3% is a dilution of 10 so you want 1 part 30% + 9 parts water. How much is 1 part?
20 mL/10 parts = 2 mL (= 1 part)
9 parts x 2 = 18 parts water. The total is 20.
To find the volume of a 30% hydrogen peroxide solution from a given volume of a 3% hydrogen peroxide solution, you can use the concept of dilution. Dilution is the process of decreasing the concentration of a solution by adding more solvent.
Here's how you can calculate the volume of the 30% hydrogen peroxide solution:
1. Start by converting the given volume of the 3% hydrogen peroxide solution to liters. Since 1 mL is equal to 0.001 L, you can convert 20 mL to 0.02 L.
2. Next, use the formula for dilution, which states that the initial concentration (C1) multiplied by the initial volume (V1) is equal to the final concentration (C2) multiplied by the final volume (V2).
Mathematically, it can be represented as: C1 * V1 = C2 * V2
In this case, the initial concentration (C1) is 3%, the initial volume (V1) is 0.02 L, and the final concentration (C2) is 30%. We want to calculate the final volume (V2).
3. Rearranging the formula, we have: V2 = (C1 * V1) / C2
Substituting the values, we get: V2 = (3% * 0.02 L) / 30%
4. Solve the equation: V2 = (0.03 L) / 0.3
Simplifying, V2 = 0.1 L
Therefore, the required volume of the 30% hydrogen peroxide solution is 0.1 liters (or 100 mL).