Physics

A 3.5 kg object is suspended from a spring of spring constant 725 N/m. Starting from the equilibrium position, the object has an initial speed of 7.9 m/s. What is the maximum displacement of the object during its subsequent motion? (In cm)

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  1. Kinetic energy at start = (1/2) m v^2
    = (1/2)(3.5)(7.9)^2
    = 109 Joules

    At the maximum displacement, it stops, so that kinetic energy has all gone into stretching the spring which stores it as potential energy
    Potential energy in spring = (1/2) k x^2
    so
    (1/2) ( 725) * x^2 = 109 Joules
    x^2 = .301
    x = .549 meters
    = 55 cm

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    posted by Damon

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