How many grams of a drug are contained in 1L of a 30% solution?
30g/100ml = Xg/1000ml solve using ratio and proportion.
Answer 300g/1000ml
3.3g
To determine the number of grams of a drug contained in 1 liter of a 30% solution, you need to know the concentration of the drug and the volume of the solution.
In this case, the concentration is given as 30%. This means that for every 100 milliliters (mL) of the solution, there are 30 grams of the drug.
To calculate the number of grams in 1 liter (1000 mL) of the solution, you can use the following proportion:
(30 grams / 100 mL) = (x grams / 1000 mL)
To solve for x, the number of grams in 1 liter, you can cross-multiply and divide:
1000 mL * 30 grams / 100 mL = 300 grams
So, there are 300 grams of the drug contained in 1 liter of a 30% solution.