A cheerleader lifts his 62.2 kg partner straight
up off the ground a distance of 0.89 m before
releasing her.
The acceleration of gravity is 9.8 m/s
2
.
If he does this 19 times, how much work has
he done?
Answer in units of J
Well, lifting up his partner 19 times sounds like quite a workout! Let's calculate the work done.
Work (W) is equal to force (F) multiplied by the distance (d) traveled. Since the cheerleader is lifting his partner straight up, the force required to lift her would be equal to her weight.
The weight of the partner can be calculated as mass (m) multiplied by the acceleration due to gravity (g). So, weight (W) = m * g.
Using this information, we can now calculate the work done per lift:
Work (W) = force (F) * distance (d)
= weight (m * g) * distance (d)
Plugging in the values:
Weight (W) = 62.2 kg * 9.8 m/s^2
= 609.16 N
Now, calculating the total work done for 19 lifts:
Total Work (TW) = Work (W) * Number of lifts
= 609.16 N * 19
= 11,560.4 N
So, the cheerleader has done approximately 11,560.4 J (joules) of work during 19 lifts. That's a pretty impressive feat! I hope he gets a well-deserved round of applause!
To find the amount of work done by the cheerleader, we can use the equation:
Work = force * distance * cos(theta)
In this case, the force exerted by the cheerleader is equal to the weight of the partner, which can be calculated using the formula:
Force = mass * acceleration due to gravity
Let's calculate the force:
Force = 62.2 kg * 9.8 m/s^2
Force = 608.36 N
Next, we can calculate the work done by the cheerleader lifting their partner a distance of 0.89 m. Since the angle at which the force is applied is not given, we assume it to be 0 degrees (horizontal). Therefore, cos(0) = 1.
Work = 608.36 N * 0.89 m * cos(0)
Work = 541.34 J
Now, we know the work done for one lift is 541.34 J. To find the total work done in 19 lifts, we multiply this value by 19.
Total work = 541.34 J * 19
Total work = 10,292.46 J
So, the cheerleader has done a total work of 10,292.46 J.