Calculate the pH of 7.2 × 10-8 M HCl. Report your answer to the hundredths place. Next, What fraction of the total H in this solution is from the HCl? Report your answer to the hundredths place.
I apologize for the re-post, but I felt the previous one was labeled incorrectly.
I answered the original post below. If that isn't appropriate you can repost at this spot and I can reorganize what I wrote.
To calculate the pH of a solution, you need to take the negative logarithm (base 10) of the concentration of hydrogen ions (H+).
Given the concentration of HCl as 7.2 × 10-8 M, we can directly convert it to pH using the formula:
pH = -log[H+]
First, calculate the [H+] concentration:
[H+] = 7.2 × 10-8 M
Taking the negative logarithm:
pH = -log(7.2 × 10-8)
Using a scientific calculator, calculate the logarithm value and then take the negative of it. The result should be reported to the hundredths place.
Now, to determine the fraction of the total H in the solution that is from HCl, we need to compare the concentration of [H+] from HCl with the initial concentration of HCl.
The initial concentration of HCl is 7.2 × 10-8 M.
The fraction of total H from HCl is given by:
([H+] from HCl) / (initial [HCl])
Substituting the values:
([H+] from HCl) = 7.2 × 10-8 M
(initial [HCl]) = 7.2 × 10-8 M
Fraction = ([H+] from HCl) / (initial [HCl])
Fraction = (7.2 × 10-8 M) / (7.2 × 10-8 M)
Simplifying, the fraction of total H from HCl is 1 or 100%.
Hence, the pH of the solution is calculated as a negative logarithm, and the fraction of total H from HCl is 100%.