How to solve titration problem for HC2H3O2 + NaOH= NaC2H3O2 + H2O
The M of NaOH= 0.427
The volume of NaOH= 17.30mL
10.00mL of acid
The second titration calculation is:
The M of NaOH= 0.427
The volume of NaOH=34.60mL
20.00mL of acid
mols NaOH = M x L = ?
mols HAc = mols NaOH (look at the coefficients in the balanced equation).
M acid = mols acid/L acid.
To solve the titration problem, you need to use the concept of stoichiometry and the volume and concentration of the chemicals involved.
1. Write the balanced chemical equation for the reaction:
HC2H3O2 + NaOH -> NaC2H3O2 + H2O
2. Determine the moles of NaOH:
Moles of NaOH = Concentration (M) × Volume (L) = 0.427 M × 0.0173 L (17.3 mL converted to L)
3. Convert moles of NaOH to moles of HC2H3O2:
The balanced equation shows a 1:1 ratio between NaOH and HC2H3O2. So, the moles of HC2H3O2 will be equal to the moles of NaOH.
4. Convert moles of HC2H3O2 to concentration:
Concentration (M) = Moles / Volume (L) = Moles of HC2H3O2 / Volume (L)
5. Calculate the concentration of HC2H3O2 for the first titration:
Moles of HC2H3O2 = Moles of NaOH
Volume (L) = 0.010 L (10.00 mL converted to L)
Concentration (M) = Moles of HC2H3O2 / Volume (L)
Plug in the values and calculate the concentration of HC2H3O2.
6. Repeat the same steps for the second titration:
Moles of HC2H3O2 = Moles of NaOH
Volume (L) = 0.020 L (20.00 mL converted to L)
Concentration (M) = Moles of HC2H3O2 / Volume (L)
Plug in the values and calculate the concentration of HC2H3O2 for the second titration.
By following these steps, you can solve the titration problem for HC2H3O2 + NaOH = NaC2H3O2 + H2O, using the given volumes and concentrations of NaOH.
To solve the titration problem, follow these steps for each calculation:
Step 1: Write the balanced equation for the reaction:
HC2H3O2 + NaOH = NaC2H3O2 + H2O
Step 2: Calculate the number of moles for the given volume and concentration of NaOH used:
moles of NaOH = (concentration of NaOH) x (volume of NaOH in L)
moles of NaOH = (0.427 M) x (17.30 mL / 1000 mL/L)
moles of NaOH = 0.007379 moles
Step 3: Determine the mole ratio between NaOH and HC2H3O2 from the balanced equation:
From the equation, the ratio of NaOH to HC2H3O2 is 1:1.
Step 4: Calculate the number of moles of HC2H3O2:
moles of HC2H3O2 = moles of NaOH
Step 5: Convert the moles of HC2H3O2 to its concentration in the given volume of acid:
concentration of HC2H3O2 = moles of HC2H3O2 / volume of HC2H3O2 in L
concentration of HC2H3O2 = moles of HC2H3O2 / (10.00 mL / 1000 mL/L)
concentration of HC2H3O2 = moles of HC2H3O2 / 0.010 L
Step 6: Repeat steps 2-5 for the second titration calculation:
moles of NaOH = (0.427 M) x (34.60 mL / 1000 mL/L)
moles of NaOH = 0.014824 moles
moles of HC2H3O2 = moles of NaOH
concentration of HC2H3O2 = moles of HC2H3O2 / (20.00 mL / 1000 mL/L)
concentration of HC2H3O2 = moles of HC2H3O2 / 0.020 L
Note: Remember to keep track of significant figures during calculations and round your final answers appropriately.