A box of chalk and 2 staplers cost $10. Three boxes of chalk and 2 staplers cost $18.Find the cost of 1 box of chalk and 1 stapler.
C+2S=10
3C+2S=18
does that help?
No it really doesnt help
To solve this problem, we can set up a system of equations:
Let's assume the cost of one box of chalk is "C" dollars and the cost of one stapler is "S" dollars.
According to the given information,
1 box of chalk + 2 staplers = $10
This can be represented as:
C + 2S = 10 --------(Equation 1)
Also, 3 boxes of chalk + 2 staplers = $18
This can be represented as:
3C + 2S = 18 --------(Equation 2)
Now, we have a system of equations (Equation 1 and Equation 2) that we can solve simultaneously to find the values of C and S.
To solve the system, there are different methods like substitution, elimination, or matrix method. Let's use the substitution method:
1. Solve Equation 1 for C:
C = 10 - 2S
2. Substitute the value of C in Equation 2:
3(10 - 2S) + 2S = 18
Simplify the equation:
30 - 6S + 2S = 18
30 - 4S = 18
3. Solve for S:
-4S = 18 - 30
-4S = -12
S = -12 / -4
S = 3
Now, we have found that the cost of one stapler is $3.
4. Substitute the value of S in Equation 1 to find C:
C + 2S = 10
C + 2(3) = 10
C + 6 = 10
C = 10 - 6
C = 4
Therefore, the cost of one box of chalk is $4.
So, the cost of 1 box of chalk and 1 stapler is $4 + $3 = $7.