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find a polynomial of least degree(having real coefficients) with zeros: 5, -2, 2i

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  1. multiply this out:

    (x-5) (x^2+4)

    I suspect you copied the problem wrong, it should be zeroes at 5, -2i, 2i

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    bobpursley
  2. Unless there is the implicit assumption that if 2i is a root, so is -2i, so the polynomial would be

    (x-5)(x+2)(x^2+4) = x^4 - 3x^3 - 6x^2 - 12x - 40

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