how would i create a 100mL solution of 0.1N nitric acid using 6.25N nitric acid?
N*mL = N*mL
0.1 N*100 mL = 6.25N * mL.
Solve for mL. That will be # mL needed of the 6.25 N solution. Make the final volume to 100 mL.
To create a 100mL solution of 0.1N nitric acid using 6.25N nitric acid, you will need to dilute the 6.25N solution with an appropriate amount of water.
To calculate the amount of 6.25N nitric acid needed, we can use the formula:
C1V1 = C2V2
Where:
C1 = initial concentration (6.25N)
V1 = initial volume (unknown)
C2 = final concentration (0.1N)
V2 = final volume (100mL)
Rearranging the formula:
V1 = (C2 * V2) / C1
Substituting the given values:
V1 = (0.1N * 100mL) / 6.25N
V1 = 1.6mL
You will need to measure 1.6mL of 6.25N nitric acid and then add water to bring the total volume up to 100mL. This will result in a 100mL solution of 0.1N nitric acid.