how would i create a 100mL solution of 0.1N nitric acid using 6.25N nitric acid?

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  1. N*mL = N*mL
    0.1 N*100 mL = 6.25N * mL.
    Solve for mL. That will be # mL needed of the 6.25 N solution. Make the final volume to 100 mL.

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