the addition of 50 g of salt to a sample of pure water causes its freezing point to be reduced from 0.0 degrees Celsius to -3.15 degrees Celsius. determine how many degrees the freezing point dropped for every 10 g of salt added.
Thank ya, randomchik.
Wait, never mind. It is 0.63, right? Well thanks anyways. ☠randomchika☠
assuming it's a linear relationship, then the change is -3.15°/50g = -0.63°/10g
thank ya steve
0.63
To determine how many degrees the freezing point dropped for every 10 g of salt added, we need to calculate the change in freezing point per gram of salt.
First, let's calculate the change in freezing point caused by adding 50 g of salt:
Change in freezing point = Initial freezing point - Final freezing point
Change in freezing point = 0.0°C - (-3.15°C)
Change in freezing point = 3.15°C
Now, let's calculate the change in freezing point per gram of salt added:
Change in freezing point per gram of salt = Change in freezing point / Mass of salt added
Change in freezing point per gram of salt = 3.15°C / 50 g
Change in freezing point per gram of salt = 0.063°C/g
So, for every 10 g of salt added, the freezing point drops by 0.063°C.