How many grams of urea [CO(NH2)2] would be required to prepare 200 mL of a 5.0 x 10-3 molar solution?
Answer
200mL of 5.0*10^-3M = 1.0*10^-3 moles of urea
so, figure mol wt and divide by 1000 to get grams needed
Answer
so, figure mol wt and divide by 1000 to get grams needed