There are a large ball and on top of it a small ball, when they both thrown together to high h, a large ball returns to hight h. To what hight does small ball reflect? (using c)
If the large ball returns to h, then the small ball returns to h also. However, in real life, the small ball will take on some of the energy of the large ball and go to a much greater height, and the large ball will not go as high.
To determine the height at which the small ball reflects, we can use the law of conservation of energy (C: Height of Original Energy is Conserved). According to this law, the total energy of a system remains constant, assuming no external factors such as air resistance.
Let's consider the initial conditions: The large ball and small ball are thrown together with an initial height of h. When they reach their maximum height, they both come to a stop momentarily before falling back down.
At the maximum height, both balls have potential energy (PE), which can be calculated using the formula PE = mgh, where m is the mass of the ball, g is the acceleration due to gravity, and h is the height.
Since both balls start at the same height and reach the same maximum height, they have the same amount of potential energy. Therefore, the potential energy of the small ball when it reflects will be equal to the potential energy of the large ball at that point.
Now, let's denote the maximum height that the small ball reflects as h'.
Using the law of conservation of energy, we can equate the potential energy of the small ball at height h' to the potential energy of the large ball at height h:
m_small * g * h' = m_large * g * h
Since the mass of the large ball and the small ball will cancel out in this equation, we get:
h' = h
Therefore, the small ball reflects to the same height it was initially thrown from, which is h.
So, the height at which the small ball reflects is equal to the height it was originally thrown, h.