On some planet other than Earth a ball is thrown upward at a velocity of 22.3 m/s. It returns back to the exact position that it started at in 8.8s. What is this planets value for "g"? (
To find the value of "g" on this planet, we can use the equation of motion for vertical motion:
h = ut + (1/2)gt^2
Where:
h = vertical displacement
u = initial velocity
g = acceleration due to gravity
t = time
In this case, the ball is thrown upward, so the initial velocity (u) is 22.3 m/s. The time taken to return back to the starting position is 8.8s.
Since the ball returns to the exact position it started from, the vertical displacement (h) is zero.
We can substitute these values into the equation and solve for "g":
0 = (22.3 * 8.8) + (0.5 * g * (8.8)^2)
Simplifying this equation gives:
0 = 195.64 + 38.72g
To solve for "g", rearrange the equation:
38.72g = -195.64
g = -195.64 / 38.72
g ≈ -5.05 m/s^2 (rounded to two decimal places)
Therefore, the value of "g" on this planet is approximately -5.05 m/s^2.