PERFORM THE INDICATED OPERATIONS AND WRITE IN STANDARD FORM 27+(sq root-9)/3
To perform the indicated operations and write the expression in standard form, let's follow the steps:
Step 1: Simplify the expression inside the square root.
In this case, the square root of -9 can be simplified as the square root of 9 times the square root of -1. The square root of 9 is 3, and the square root of -1 is denoted as "i" (the imaginary unit). Therefore, the square root of -9 simplifies to 3i.
Step 2: Rewrite the expression with the simplified square root.
The expression becomes:
27 + (3i/3)
Step 3: Simplify 3i/3.
Dividing 3i by 3 results in i.
Step 4: Rewrite the simplified expression in standard form.
Adding 27 and i gives the final expression: 27 + i.
Therefore, the simplified expression in standard form is 27 + i.