6th Grade Math:
Write 144 as a product of prime factors. Then write the prime factorization using exponents.
Study this site.
http://www.mathsisfun.com/prime-factorization.html
I'll be glad to check your answer.
I know how to do it but i can't find 2 prime numbers for 144.
144 = 2 * 2 * 2 * 2 * 3 * 3
2 to the 4th power and 3 to the 2nd power.
The only two prime numbers are 2 and 3.
http://www.miniwebtool.com/list-of-prime-numbers/?to=300
Thanks Jaden and Maci! :)
Thanks Ms. Sue :D!
To find the prime factorization of a number, you need to find all the prime numbers that divide the given number evenly. Let's find the prime factors of 144 step by step:
Step 1: Start by dividing 144 by the smallest prime number, which is 2. We get 144 ÷ 2 = 72.
Step 2: Now, divide 72 by 2 again to get 36: 72 ÷ 2 = 36.
Step 3: Continue dividing 36 by 2 to get 18: 36 ÷ 2 = 18.
Step 4: Divide 18 by 2 once again to get 9: 18 ÷ 2 = 9.
Step 5: At this point, we can't divide 9 any further by 2. So, we move to the next prime number, which is 3, and divide 9 by 3. We get 9 ÷ 3 = 3.
Step 6: Now, we are left with the prime number 3, which cannot be further divided. Therefore, we can stop here.
To summarize, the prime factors of 144 are 2, 2, 2, 2, 3, and 3.
Now, let's express the prime factorization using exponents:
2 × 2 × 2 × 2 × 3 × 3 can be written as 2^4 × 3^2.
So, the prime factorization of 144 using exponents is 2^4 × 3^2.