How do I use the distributive property to write (e+f)(-5) as an equivalent algebraic expression?
just think of the way you do it with numbers
5(2+3) = 5*2 + 5*3 = 10 + 15 = 25
(e+f)(-5) = e(-5) + f(-5) = -5e -5f
n+2x10 when n=5
To use the distributive property to write the expression (e+f)(-5) as an equivalent algebraic expression, you need to distribute the -5 to both terms inside the parentheses.
The distributive property states that for any numbers a, b, and c, a(b + c) is equal to ab + ac.
Applying this property to (e+f)(-5), you can distribute -5 to both e and f:
(-5)e + (-5)f
This simplifies to:
-5e - 5f
Therefore, the equivalent algebraic expression is -5e - 5f.
To use the distributive property to write the expression (e+f)(-5) as an equivalent algebraic expression, you need to distribute the -5 to both e and f.
The distributive property states that a(b + c) = ab + ac.
Applying this property to the expression (e+f)(-5), we can rewrite it as -5e - 5f.
So, the equivalent algebraic expression to (e+f)(-5) is -5e - 5f.