it is a 6 digit number. there is no repetition of digits. It is divisible by 5 and is more than 3000,000. The digit in the hundreds place is 3 more than the digit in the ones place. The digit in the ten thousands place is 3 times the digit in the hundred thousands place. The digit in the thousands place is half the value of the digit in the hundreds place.
the difference between the digits in the tens place and the thousands place is 2.
I copied it from the page I got it from - hummm? so 3,000,000 cant be a 6 digit # can it? Maybe its 300,000
since no mention is made of the millions digit, let's assume it is in fact 6 digits and more than 300,000.
10,000 = 3*100,000, so 100,000 digit is 3, 10,000 = 9. Anthing other than 3 must be greater than 3, so 3 times it will exceed 9.
93xxxx
Divisible by 5 means the ones digits is 5 or 0:
39xxx0 or 39xxx5
hundreds = ones + 3, so 3 or 8
39x3x0 or 39x8x5
no repeats means 39x8x5
thousands = 1/2 of hundreds = 4
3948x5
thousands - tens = 2 or -2
394825
394865
To find the 6-digit number that meets all these conditions, we can break down the problem and solve it step by step.
1. Divide by 5: Since the number is divisible by 5, the units place must be either 0 or 5. However, since there is no repetition of digits, the units place cannot be 0. Thus, the units place must be 5.
2. The hundreds place is 3 more than the ones place: Since the units place is 5, the hundreds place must be 8 (5 + 3 = 8).
3. The difference between the digits in the tens place and the thousands place is 2: We are given that the difference is 2. Since the tens place has to be smaller than the thousands place for a positive difference, the tens place must be either 3 or 4. However, as the digit in the thousands place is half the value of the digit in the hundreds place, the hundreds place cannot be 8 (because half of 8 is not an integer). Therefore, we can conclude that the tens place is 3, and the thousands place is 5 (3 + 2 = 5).
4. The digit in the ten thousands place is 3 times the digit in the hundred thousands place: Since the number is more than 300,000 and the digit in the thousands place is 5, the ten thousands place must be either 1 or 2. However, as the digit in the ten thousands place is 3 times the digit in the hundred thousands place, it cannot be 1. Thus, the digit in the ten thousands place must be 2, and the digit in the hundred thousands place is 1 (2 = 3 * 1).
Now, with all the digits determined, we can form the number:
100,000 + 10,000 + 5,000 + 800 + 50 + 5 = 116,855
Therefore, the 6-digit number that meets all the given conditions is 116,855.