In a vertical dive a peregrine falcon can accelerate at 0.6 times the free-fall acceleration (that is at 0.06g) in reaching the speed of about 100 m/c. If a falcon pulls out of a dive into a circular arc at this speed and can sustain a radial acceleration of 0.6 g, what is the radius of the turn?
To find the radius of the turn, we need to use the concept of centripetal acceleration and the relationship between radial acceleration and centripetal acceleration.
Let's start by finding the centripetal acceleration of the falcon during the turn. Centripetal acceleration is given by the formula:
ac = v^2 / r
Where:
- ac is the centripetal acceleration
- v is the velocity of the falcon
- r is the radius of the turn
We know that the falcon can sustain a radial acceleration of 0.6 g. Since free-fall acceleration is g (9.8 m/s^2), the radial acceleration can be represented as 0.6g. Hence:
ac = 0.6g
We also know that the speed of the falcon during the turn is 100 m/s, so we can substitute those values into the equation:
0.6g = (100)^2 / r
Now, we can solve for the radius (r):
r = (100)^2 / (0.6g)
To calculate the radius, we will need the value of g. Assuming g is approximately 9.8 m/s^2, we can substitute that value into the equation:
r = (100)^2 / (0.6 * 9.8)
Calculating the expression gives us the value of the radius.
6000
well you muiltiply 3 by the amount of helicopters. and subtract 6 by 7 and you get 13. 13 is the answer.
0.6 times the free fall acceleration is not 0.06 g.
m/c is not a unit of speed.
You need to be more careful typing your questions.
Use the formula V^2/R = 0.6 g to solve for the turn radius, R.