six times some number added to 6 amounts to 33 added to the product of 3 and the number
a)27 b)-27 c)-9 d)9
6n + 6 = 33 + 3n
3n = 27
n = ?
Answer is n=24
Answer is n=27 not 24 sorry.
You have to divide both sides by 3 which should get you 9
A number plus 6 amounts to -33
To solve this problem, let's assign a variable to the unknown number. Let's call the unknown number "x".
According to the given information, "six times some number added to 6" can be written as 6x + 6.
"33 added to the product of 3 and the number" can be written as 33 + 3x.
Now we can set up the equation:
6x + 6 = 33 + 3x
To solve for x, we want to isolate the variable on one side of the equation. Let's start by moving the 3x term to the left side of the equation by subtracting 3x from both sides:
6x - 3x + 6 = 33
Simplifying the left side of the equation gives us:
3x + 6 = 33
Next, let's isolate the variable by subtracting 6 from both sides:
3x = 33 - 6
Simplifying the right side of the equation gives us:
3x = 27
Now, divide both sides of the equation by 3:
(3x)/3 = 27/3
x = 9
So, the answer is d) 9.