How long does it take an automobile traveling
74.3 km/h to become even with a car that is
traveling in another lane at 58.3 km/h if the
cars’ front bumpers are initially 114 m apart?
Answer in units of s
they approch each other at
74.3-58.3 = 16 km/h
.114 km = 16 * h
h = .007125 h
times 3600 seconds/hr = 25.65 seconds
To solve this problem, we can use the formula:
Time = Distance / Speed
First, we need to find the relative distance between the two cars. Since the front bumpers are initially 114 meters apart, the initial relative distance is 114 meters.
Next, we need to find the relative speed between the two cars. It is the difference between the speeds of the two cars:
Relative Speed = Speed of the first car - Speed of the second car
= 74.3 km/h - 58.3 km/h
To convert the speeds into meters per second, we need to multiply by a conversion factor:
Relative Speed = (74.3 km/h - 58.3 km/h) * (1000 m / 1 km) * (1 h / 3600 s)
= (16 km/h) * (1000 m / 1 km) * (1 h / 3600 s)
Now, we can calculate the time it takes for the two cars to become even by dividing the relative distance by the relative speed:
Time = Distance / Speed
= 114 m / ((16 km/h) * (1000 m / 1 km) * (1 h / 3600 s))
Simplifying the expression:
Time = 114 m / (16 * 1000 * (1 / 3600))
= 114 m / (16 * 1000 / 3600)
= 114 m * (3600 / (16 * 1000))
= 114 m * 0.225
= 25.65 s
Therefore, it will take approximately 25.65 seconds for the two cars to become even.