A sample of sodium reacts completely with 0.568 of chlorine, forming 936 of sodium chloride. What mass of sodium reacted?
0.568 what?
936 what?
After you fill in the units you will have a stoichiometry problem. Here is a worked example of such a problem; just follow the steps.
http://www.jiskha.com/science/chemistry/stoichiometry.html
A sample of sodium reacts completely with 0.568 kg of chlorine, forming 936 g of sodium chloride. What mass of sodium reacted?
the value and Units
To find the mass of sodium that reacted, we need to calculate it based on the balanced chemical equation and the given amount of sodium chloride formed.
The balanced chemical equation for the reaction between sodium and chlorine is:
2 Na + Cl2 → 2 NaCl
From the equation, we can see that 2 moles of sodium react with 1 mole of chlorine to form 2 moles of sodium chloride.
First, we need to calculate the number of moles of sodium chloride formed. We can use the formula:
moles = mass / molar mass
Given that the mass of sodium chloride formed is 936 g and the molar mass of sodium chloride is 58.44 g/mol, we can calculate the number of moles of sodium chloride:
moles of sodium chloride = 936 g / 58.44 g/mol ≈ 16 moles
Since 2 moles of sodium react with 2 moles of sodium chloride, the number of moles of sodium that reacted is also 16 moles.
Finally, we can calculate the mass of sodium that reacted using the formula:
mass = moles × molar mass
molar mass of sodium = 22.99 g/mol
mass of sodium = 16 moles × 22.99 g/mol ≈ 367.84 g
Therefore, the mass of sodium that reacted is approximately 367.84 grams.
To find the mass of sodium that reacted, we need to use the information given in the problem.
1. First, write down the balanced chemical equation for the reaction between sodium (Na) and chlorine (Cl2), which forms sodium chloride (NaCl):
2 Na + Cl2 -> 2 NaCl
This equation tells us that 2 moles of sodium react with 1 mole of chlorine to form 2 moles of sodium chloride.
2. Next, calculate the molar mass of sodium chloride (NaCl). The molar mass is the sum of the atomic masses of all the atoms in one formula unit of a substance.
The atomic mass of sodium (Na) is 22.99 g/mol, and the atomic mass of chlorine (Cl) is 35.45 g/mol. Therefore, the molar mass of sodium chloride (NaCl) is:
Molar mass of NaCl = (1 × 22.99 g/mol) + (1 × 35.45 g/mol) = 58.44 g/mol
3. Now we can use stoichiometry to calculate the number of moles of sodium that reacted. We know that the reaction formed 936 grams of sodium chloride (NaCl).
Number of moles of NaCl = Mass of NaCl / Molar mass of NaCl
Number of moles of NaCl = 936 g / 58.44 g/mol ≈ 16 moles
Since the balanced chemical equation tells us that 2 moles of sodium react with 2 moles of sodium chloride, we can say that 16 moles of sodium chloride react with:
(16 moles of NaCl) × (2 moles of Na / 2 moles of NaCl) = 16 moles of Na
4. Finally, we need to convert the number of moles of sodium back into mass. The molar mass of sodium (Na) is 22.99 g/mol.
Mass of Na = Number of moles of Na × Molar mass of Na
Mass of Na = 16 moles × 22.99 g/mol ≈ 367.84 g
So, the mass of sodium that reacted is approximately 367.84 grams.