if an egg is thrown at an initial height of 1.9m and lands 2.09s later at 19m what is the velocity at which the egg was thrown and the velocity with which it lands
a. R = Xo * T = 19 m.
Xo * 2.09 = 19
Xo = 9.1 m/s.=Hor. velocity at which egg was thrown.
b. V^2 = Vo^2 + 2g*d.
V^2 = 0 + 19.6*1.9 = 37.24
V = 6.1 m/s.