The blck mamba is one of the world's most poisonous snakes, and with a maximum speed of 18.0 km/h, it is also the fastest. Suppose a mamba waiting in a hide-out sees prey and begins slithering toward it with a velocity of +18.0 km/h. After 2.50 s, the mamba realizes that its prey can move faster than it can. The snake then turns around and slowly returns to its hide-out in 12.0 s. Caclulate the mamba's average velocity suring its return to the hideout.
To calculate the mamba's average velocity during its return to the hideout, we need to determine the total displacement and the time taken.
We can start by finding the total displacement of the mamba during its return to the hideout. Since the mamba is returning to its starting point, the displacement will be zero.
Next, we need to find the time taken for the return journey. Given that the mamba takes 12.0 seconds to return, we have the time as -12.0 s. The negative sign indicates that the direction is opposite to the initial positive direction of +18.0 km/h.
Finally, we can calculate the average velocity using the formula:
Average Velocity = Total Displacement / Time
Since the displacement is zero, the average velocity will also be zero.
Therefore, the mamba's average velocity during its return to the hideout is 0 km/h.