Find the second and fifth terms of A(n)=22+(n-1)11 and A(n)=-2+(n-1)(-2)
For the first equation
A(n) = 22 + (n-1)(11)
A(2) = 22 + (1)(11) = 33
A(5) = 22 + 4(11) = 66
You do the second equation in the same way
To find the second and fifth terms of the sequences described by the expressions A(n) = 22 + (n-1)11 and A(n) = -2 + (n-1)(-2), we need to substitute the values of n for which we want to find the terms.
For A(n) = 22 + (n-1)11:
To find the second term (n = 2):
A(2) = 22 + (2-1)11
A(2) = 22 + 1(11)
A(2) = 22 + 11
A(2) = 33
To find the fifth term (n = 5):
A(5) = 22 + (5-1)11
A(5) = 22 + 4(11)
A(5) = 22 + 44
A(5) = 66
Therefore, the second term is 33, and the fifth term is 66.
For A(n) = -2 + (n-1)(-2):
To find the second term (n = 2):
A(2) = -2 + (2-1)(-2)
A(2) = -2 + 1(-2)
A(2) = -2 + (-2)
A(2) = -4
To find the fifth term (n = 5):
A(5) = -2 + (5-1)(-2)
A(5) = -2 + 4(-2)
A(5) = -2 + (-8)
A(5) = -10
Therefore, the second term is -4, and the fifth term is -10.