A metal ring with a mass of 18.36 g undergoes a change in temperature of 26.37 oC. The energy change, or heat, required for this change in temperature is 1508 Joules.
What is the specific heat of the ring?
q = mass x sp.h. x delta T.
Substitute and solve for sp.h.
so
1508=18.36*26.37*x?
Yes and solve for x.
Yes the answer is correct and thank you so much I find this website so helpful!
To find the specific heat of the ring, we can use the formula:
Q = m * c * ΔT
where:
Q is the heat energy transferred,
m is the mass of the ring,
c is the specific heat capacity,
ΔT is the change in temperature.
We are given:
Q = 1508 Joules
m = 18.36 g
ΔT = 26.37 °C
To find the specific heat, we need to rearrange the formula:
c = Q / (m * ΔT)
Let's calculate the specific heat.