Your friend weighs 145 lb. What is her mass in kilograms if she went to the moon where the acceleration of gravity is 1/6 that on earth?
i know that her weight in newtons is 652.5, and that her mass in kilograms is 65.25, and that her weight in newtons if she went to the moon where the acceleration of gravity is 1/6 that on earth is 108.7 so i was thinking that since one N = 10 kg(right?) it would be 10.87 kg but that is wrong. help?
=38.5
To find the mass of your friend in kilograms when she is on the moon, you need to apply the principles of weight, mass, and the acceleration of gravity.
Let's begin by understanding the relationship between weight and mass. On Earth, weight is equal to the mass of an object multiplied by the acceleration due to gravity. This is often represented by the equation:
Weight = Mass × Acceleration due to Gravity
On Earth, the acceleration due to gravity is approximately 9.8 m/s². So, your friend's weight on Earth can be calculated as:
Weight on Earth = Mass × 9.8
You correctly calculated her weight on Earth as 652.5 N. Now, let's calculate her mass on Earth using this equation:
Mass = Weight on Earth / 9.8
Substituting the value you provided, the mass on Earth is:
Mass on Earth = 652.5 N / 9.8 = 66.73 kg (rounded to two decimal places)
Next, let's move on to the moon. The acceleration due to gravity on the moon is approximately 1/6th that of Earth's gravity. So, the equation for calculating weight on the moon becomes:
Weight on Moon = Mass × (1/6) × 9.8
Given her weight on the moon is 108.7 N, we can calculate her mass on the moon using this equation:
Mass on Moon = Weight on Moon / ((1/6) × 9.8) = 108.7 N / 1.6333... ≈ 66.73 kg / 1.6333... ≈ 40.88 kg (rounded to two decimal places)
Therefore, your friend's mass on the moon would be approximately 40.88 kg.
It's important to note that 1 Newton (N) is not equivalent to 10 kilograms (kg). The Newton is a unit of force, while the kilogram is a unit of mass. The conversion between the two is only accurate when gravitational force is involved.