if y varies direct as 8, and y is -60 when x is -5, find y when x is 3.
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Assume y's direct function is either a multiplication or division; I chose the second one. So a trial shows y at -60 = x at (-5 + const 1) x const 2 all divided by 8. If const 1 is -43, then -5 + (-43) = -48 x const 2 divided by 8. This solves for -60, the value of y, so const 2 is 10. When you solve for x=3, the y = +3-43 or -50. Solving the equation for x=0, works out to y =~-54, which checks graphically.
To solve this problem, we can use the concept of direct variation. When two variables y and x vary directly, it means that they can be expressed as y = kx, where k is a constant.
In this problem, we know that y varies directly as 8. This means that y = kx, where k is 8.
We are given that when x is -5, y is -60. We can use this information to solve for the value of k.
Substituting the given values into the direct variation equation, we get -60 = 8(-5).
Simplifying this equation gives us -60 = -40.
To find the value of y when x is 3, we can use the value of k that we just found. Substituting x = 3 into the direct variation equation, we get y = 8(3).
Simplifying this equation gives us y = 24.
Therefore, when x is 3, y is 24.