Conductor "A" has a charge of +6 and conductor "B" has a charge of -8. If the 2 objects are brought together and then separated, what will be the chage on each object?

Charge will flow from one conductor er until they are at the same electrical potential. If the two conductors are the same size and ide shape, such as equal radius spheres, then equipotential requires that they have the same charge. Since a net excess charge of -2 is available, there would be a charge of -1 on each one. That charge would remain as they are separated.

If the two conductrs are different in size, the results would be differen. Was your problem accompanied by a figure that showed the size and shape of the two conductors?

To determine the charge on each object after they are brought together and then separated, we need to understand the concept of charge transfer and the principle of conservation of charge.

When two objects with different charges are brought together, the charges on both objects redistribute according to the principle of conservation of charge. This principle states that the overall charge of an isolated system remains constant. In other words, charge is neither created nor destroyed, only transferred.

In this scenario, conductor "A" has a charge of +6 and conductor "B" has a charge of -8. When they are brought together, the charges redistribute until they reach a state of electrostatic equilibrium. In this equilibrium state, the total charge on the combined system will remain the same as before. Therefore, the total charge on the combined system is +6 - 8 = -2.

Now, let's determine the charges on each conductor after they are separated. Since the total charge of the combined system is -2, one of the conductors must have a positive charge while the other has a negative charge, since they started off with opposite charges.

The specific charge on each conductor depends on their relative sizes and separation. However, we can determine the charges by considering that they started with a total charge of +6 and -8, respectively:

Conductor "A" would have a negative charge: -2 / (6 + 8) * 6 = -0.75

Conductor "B" would have a positive charge: -2 / (6 + 8) * 8 = +1.25

Therefore, after they are separated, conductor "A" would have a charge of -0.75 and conductor "B" would have a charge of +1.25.