What are the products of Ba(NO3)2(aq)+K2CO3(aq)?
BaCO3(s) + 2KNO3(aq)
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To determine the products of the reaction between Ba(NO3)2(aq) and K2CO3(aq), we need to understand the solubility rules and double displacement reactions.
1. Ba(NO3)2 dissociates into Ba^2+ and 2 NO3^- ions.
Ba(NO3)2(aq) → Ba^2+(aq) + 2 NO3^-(aq)
2. K2CO3 dissociates into 2 K^+ ions and CO3^2- ion.
K2CO3(aq) → 2 K^+(aq) + CO3^2-(aq)
In a double displacement reaction, the cations of one compound combine with the anions of the other compound to form new compounds.
As a result, the Ba^2+ ion will combine with the CO3^2- ion to form an insoluble BaCO3 compound. The K^+ ions will remain unchanged as they are spectator ions.
Hence, the products of the reaction are:
Ba(NO3)2(aq) + K2CO3(aq) → BaCO3(s) + 2 KNO3(aq)
The balanced equation for this reaction is:
Ba(NO3)2(aq) + K2CO3(aq) → BaCO3(s) + 2 KNO3(aq)
Therefore, the products of the reaction are solid BaCO3 and aqueous KNO3.
To determine the products of a chemical reaction, we need to consider the reactants and the types of chemical reactions involved. In this case, we have the reactants Ba(NO3)2 (barium nitrate) in aqueous solution and K2CO3 (potassium carbonate) in aqueous solution.
To determine the products, we can follow these steps:
1. Identify the ions present in the reactants:
- Ba(NO3)2 dissociates into Ba2+ and 2NO3- ions.
- K2CO3 dissociates into 2K+ and CO3^2- ions.
2. Determine if any precipitates will form:
Looking at the combination of ions, we can see that Ba2+ ions from Ba(NO3)2 can react with CO3^2- ions from K2CO3 to form an insoluble compound, barium carbonate (BaCO3). This reaction is known as a precipitation reaction.
3. Write the balanced chemical equation:
Ba(NO3)2(aq) + K2CO3(aq) → BaCO3(s) + 2KNO3(aq)
So, the products of the reaction between Ba(NO3)2 and K2CO3 are barium carbonate (BaCO3) as a solid precipitate and potassium nitrate (KNO3) in aqueous solution.