What is the amount of heat involved in each of the following?kilojoules to heat 240 of gold from 20 to 188
To calculate the amount of heat involved in heating 240 grams of gold from 20°C to 188°C, you need to use the formula:
Q = m * c * ΔT
Where:
Q is the heat involved,
m is the mass of the substance (in grams),
c is the specific heat capacity of the substance (in joules per gram degree Celsius),
ΔT is the change in temperature (in degrees Celsius).
The specific heat capacity of gold is approximately 0.129 J/g°C.
First, convert the mass of gold from grams to kilograms:
240 grams = 0.24 kilograms
Next, calculate the change in temperature:
ΔT = final temperature - initial temperature
ΔT = 188°C - 20°C
ΔT = 168°C
Now, substitute the values into the formula:
Q = 0.24 kg * 0.129 J/g°C * 168°C
To convert the result to kilojoules, divide by 1000:
Q = (0.24 kg * 0.129 J/g°C * 168°C) / 1000
Q ≈ 5.186 kilojoules
Therefore, the amount of heat involved in heating 240 grams of gold from 20°C to 188°C is approximately 5.186 kilojoules.
To calculate the amount of heat involved in heating gold from 20 to 188 degrees Celsius, you need to consider the specific heat capacity of gold and the change in temperature. The specific heat capacity of gold is 0.129 J/g°C.
Given:
Mass of gold = 240 grams
Initial temperature = 20°C
Final temperature = 188°C
Step 1: Calculate the change in temperature (∆T)
∆T = Final temperature - Initial temperature = 188°C - 20°C = 168°C
Step 2: Calculate the amount of heat (q) using the formula:
q = mass (in grams) × specific heat capacity (in J/g°C) × ∆T
q = 240 g × 0.129 J/g°C × 168°C
Step 3: Convert the answer to kilojoules (kJ)
1 kilojoule (kJ) = 1000 joules (J)
q (in kJ) = q (in J) ÷ 1000
Now, let's solve for q:
q = 240 g × 0.129 J/g°C × 168°C
q = 5304.96 J
q (in kJ) = 5304.96 J ÷ 1000
q ≈ 5.305 kJ
Therefore, the amount of heat involved in heating 240 grams of gold from 20 to 188°C is approximately 5.305 kilojoules (kJ).